My joe cell

Hi Peter,

the water level, usually, should be around 1\” below the tops of the tubes. See this picture.
http://www.thelastfourbooks.com/Kabbalah/Joe_Cell/Joe_Cell_Stage_3c.jpg
This is from my Joe cell archives page.
http://www.david-house-productions.com/House-of-David/alternative_energy/joe_cell.html#Joe_Pics

You\’ll notice that the water level is around even with the tops of the tubes, but NOTE: this is because it is a water charging kit and not the actual joe cell that is installed in the car.

Hi Peter,

I am assuming you mean that you\’re looking for a cell in ball shape. Is that right?

You have come to the right place since I invented and designed the Moe-joe cell, which is the spherical joe cell.

go to my website here – http://www.moe-joe-cell.com and then come back and post to the moe-joe cell forum.

i usually use goop to seal the outside of the moe-joe cell spheres, and yes, this does work to create negative cell.

Peter smith wrote:
What is the \”Goop\” – it is material or part of something>>

it is a GLUE which works very nicely. cleans up well too. all in one piece, not annoying like silicone which never really comes off very well.

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Hi Peter,

I supply these spheres, as hemispheres.
it\’s a very inexpensive way to get the cells, believe me.

http://www.nutopia.cc/store?page=shop.browse&category_id=12

Peter,

you don\’t need 2 mm.
My moe-joe cells are made from 22 gauge steel, which is
.0253\” thick which is 0.642mm… This is very stable steel.
I believe you could even use so thin as 24 gauge – .0201\” which is 0.51mm – but this is the very thinnest I would go.

And it is tooo expensive to SPIN the cells.
You have to look for Metal Stampers.

Peter smith wrote:

good luck Peter.

I dn\’t understand the question. can you rephrase the question please?

I think both 25mm and 30mm is quite small to have as the smallest size.
it is not even 1.5\” in diameter, for the 30mm.
the sizes themselves are okay.

30mm and 60mm will resonate with each other, bc it is 2X – the octave in size. so no problem.
120 mm is 2X 60mm which is fine – 2x is the octave and will also resonate.
120mm is 4x the size of 30mm which is fine.

the trouble you run into is the 90mm size is 3X the size of the 30mm, which when dealing with any given ROOT frequency, eg C note – 1046.50 Hz, when you apply the ratio to size, we look to a lower frequency for a larger sphere, and the ratio of the frequency is diminished by 3X (related to the volume) so the volume is affected by 27 times (because for sphere volume is r-to the power of 3) so 3x to power of 3 = 27.
So with frequency of 1046.50hz divided by 27 – we arrive at frequency of 38.76 which is very close to D#1/Eb1 38.89 Hz
This is a very dissonant note.

So they are all RESONANT with each other, GOOD, but the 90mm is NOT.
I do not think it is possible to keep the same spaces, 30 – 30 – 30 between them and to have 4 spheres, equally spaced, and to have a good resonance with all of them.
you would have to have different sizes.

Peter smith wrote:

hi Peter.
It is my calculations, nowhere is there a link.
In some other literature, you can calculate resonant frequency of a SOLID sphere, for instance, if you know the material used. I am assumining that the WATER is all the same, so it is really a matter of VOLUME which determines the resonance of the size.

use this page to calculate the volume –

http://www.calculatorfreeonline.com/calculators/geometry-solids/sphere.php

Now, when we have 2x the size, for instance
(1 millimeter = 0.0393700787 inches)
30mm = 1.1811\” – Volume = 6.90162 in3
60mm = 2.3622\” – Volume = 55.21298 in3

divide 6.90162 by 55.21298 to get RATIO.

Go to http://www.phy.mtu.edu/~suits/notefreqs.html
to get Frequencies.
We do not know exactly what the FREQUENCY is going to be for any sphere because of many unknown factors. We can only imagine that the inner sphere is the ROOT note and then compare frequencies based on relative volumes.

therefore, 6.90162 divided by 55.21298 = 0.125

So if we imagine that our ROOT note is C7 – 2093.00 Hz,
then the LARGER VOLUME sphere will be 0.125 (or 1/8th) the frequency, because as a sphere gets larger in volume, it gets a lower frequency – sounds DEEPER.

So… 2093 x 0.125 Hz (1/8) =
261.625 Hz which when we look at the page on frequencies we see this is – C4 261.63 Hz – EXACTLY the 3rd lower OCTAVE, which proves that frequencies will be resonant when the diameters of the spheres are DOUBLES of each other, because doubles are OCTAVES in frequencies – this is also true for lengths of wires, coils, etc.

We know the 120mm sphere is good too!! because it is 4X the size of the root sphere and 2X the size of the 2nd sphere.

Okay – so what you have to do is look for the 3rd sphere diameter to be some resonant frequency (which is an octave, a major 3rd, major 5th) of your root note.

Do you understand?
Let me know if you have any questions.

About Goop – i believe it is silicone based…
but has other ingredients which makes it easy to clean.

1,1,2,3,5,8…

1 and 2 is good, cause it is double.
1-3 is 3X – very dissonant relative frequency, and
2 – 3 is very dissonant too.
2\” – V = 33.51032 in3
3\” – V = 113.09734 in3

Ratio – 33.51 / 113.09734 = 0.29629
So if 1\” is root note – 2\” is a lower octave, so it is essential the same as the root note, only lower, so –
if we take any given root note – C again – 2093 Hz –
and apply that ratio (0.29629) we get – 620.14 Hz which is basically D#5/Eb5 622.25 – this is a Flat 3rd – minor 3rd, which is sad and dissonat. NOT good.

so… i don\’t like the fibonacci sequence for the sizes.